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The problem

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We are using Knewton during the Virus, Knewton shows the answer to this equation as 290 miles and do your math show 200 mph.

It's 4 5/6x60

Scott drove for 4 5/6 hours @ 69 mph. What distanced did he travel? Is that correct?

Answer provided by our tutors

Let

t = 4 5/6 hours is the time of the travel

v = 60 mph is the average velocity

d = the distance traveled

Since v = d/t we have d = v*t

d = (4 5/6)*60

You are getting the wrong answer because you have typed in:

  

In order to get the right answer you need to type in:

This way you will get the correct result:

d = 290 mi

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