Factoring a Difference or a Sum of Two Cubes
We can divide a3 - b3 by a - b and get the quotient
a2 + ab + b2 and no remainder. So a - b is a factor of a3
- b3, a difference of
two cubes. If you divide a3 + b3 by a + b, you will get the quotient
a2 - ab + b2 and no remainder. Try it. So a + b is a factor of a3
+ b3, a sum of
two cubes. These results give us two more factoring rules.
Factoring a Difference or a Sum of Two Cubes
a3 - b3 = (a - b)(a2 + ab + b2)
a3 + b3 = (a + b)(a2 - ab + b2)
Example 1
Factoring a difference or a sum of two cubes
Factor each polynomial.
a) x3 - 8
b) y3 + 1
c) 8z3 - 27
Solution
a) Because 8 = 23, we can use the formula for factoring the difference of two
cubes. In the formula a3 - b3 = (a - b)(a2
+ ab + b2)
, let a = x and b = 2:
x3 - 8 = (x - 2)(x2 + 2x + 4)
| b) y3 + 1 |
= y3 + 13 |
Recognize a sum of two cubes. |
| |
= (y + 1)(y2 - y + 1) |
Let a = y and b = 1 in the formula
for the sum of two cubes. |
| c) 8z3 - 27 |
= (2z)3 - 33 |
Recognize a difference of two cubes. |
| |
= (2z - 3)(4z2 + 6z + 9) |
Let a = 2z and b = 3 in the formula
for a difference of two cubes. |